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daser333 [38]
1 year ago
8

Question 10: Each tablet in a bottle of 30 costs the pharmacy $4.60. The pharmacy has additional costs including supplies and sh

ipping of $1.40 per pill. If a 12% profit is desired, how much would the pharmacy charge for entire bottle?
Mathematics
1 answer:
valentinak56 [21]1 year ago
8 0

The pharmacy should charge $201.6 for the entire bottle

Cost price refers the  price the seller bought the product

Selling price refers to the price the seller sells to the consumer.

Profit refers to the money earned by the seller above the cost price

Loss refers to the money paid by the seller above the cost price.

Profit= SP-CP

CP=30X$4.60=$138

TOTAL EXPENSES=$138+30X$1.40

                                = $180

FOR PROFIT OF 12%,the seller must sell in= $180(1+12/100)

                                                                         =$201.6

Therefore,the pharmacy should charge $201.6 for the entire bottle to make a profit of atleast 12%

Learn more about profit and loss,

brainly.com/question/19104371

#SPJ10

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Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

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Putting values in above equation, we get:

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The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

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k = rate constant = 0.01506days^{-1}

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a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

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