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Stolb23 [73]
3 years ago
10

You are in a submarine and are at the surface of the ocean but out in the deep sea. There is a big storm and you want to dive do

wn deep enough so that you avoid the turbulence of the sea. You notice the distance between successive waves (wave length) is 20 meters. How far down do you need to dive down to not feel the effect of the waves?

Physics
1 answer:
vfiekz [6]3 years ago
4 0

One of the maritime principles that relate the turbulence and wavelength of the waves is called the "depth of 1/2 wavelength" which is also usually referred to as the floor of the wave: A point of depth in which There is no movement. There if a submarine is found, it can be unbalanced and steadily navigate.

If the wavelength is 20 meters, then it must be submerged 10 meters (20/2) to avoid turbulence.

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A car moves at a constant velocity of 30 m/s and has 3.6 × 105 J of kinetic energy. The driver applies the brakes and the car st
LekaFEV [45]

The force needed to the stop the car is -3.79 N.

Explanation:

The force required to stop the car should have equal magnitude as the force required to move the car but in opposite direction. This is in accordance with the Newton's third law of motion. Since, in the present problem, we know the kinetic energy and velocity of the moving car, we can determine the mass of the car from these two parameters.

So, here v = 30 m/s and k.E. = 3.6 × 10⁵ J, then mass will be

K.E = \frac{1}{2} * m*v^{2}  \\\\m = \frac{2*KE}{v^{2} } = \frac{2*3.6*10^{5} }{30*30}=800 kg

Now, we know that the work done by the brake to stop the car will be equal to the product of force to stop the car with the distance travelled by the car on applying the brake.Here it is said that the car travels 95 m after the brake has been applied. So with the help of work energy theorem,

Work done = Final kinetic energy - Initial kinetic energy

Work done = Force × Displacement

So, Force × Displacement = Final kinetic energy - Initial Kinetic energy.

Force * 95 = 0-3.6*10^{5}\\ \\Force =\frac{-3.6*10^{5} }{95}=-3.79 N

Thus, the force needed to the stop the car is -3.79 N.

5 0
3 years ago
Someone plz help me ? what instruments did Copermicus and Tycho Brahe use ??
balandron [24]
Astrolabes and quadrants
6 0
3 years ago
What is the frequency of highly energetic ul-
Mnenie [13.5K]

Frequency = (speed) / (wavelength)

Frequency = (3 x 10⁸ m/s) / (124 x 10⁻⁹ m)

Frequency = <em>2.42 x 10¹⁵ Hz</em>

8 0
3 years ago
DetermiOne of the lines in the Balmer series of the hydrogen atom emission spectrum is at 397 nm. It results from a transition f
larisa86 [58]

Answer:

a)n =7 , b) n = 5

Explanation:

The energy levels of the hydrogen atom is described by the Bohr model

       E_{n} = - 13.606   1/n²

This equation energy is given in elector volts and n is an integer

A transition occurs when the electro sees from a superior to a lower state

       E₀ - E_{n} = -13.606 (1/n_{f}² - 1/n₀²)

Let's apply this expression

         n₀ = 2

Let's look for the energy of the different levels and subtract it

n₀          E_{n} (eV)

1            -13,606

2            -3.4015

3           - 1.5118

4           -0.850375

5           -0.54424

6           -0.3779

7           -0.2777

The wavelength of the transition is 397 nm = 397 10⁻⁹ m

The speed of light is related to wavelength and frequency

       c = λ f

The Planck equation gives the energy of a transition

      E = h f

      E = h c /λ

Let's calculate

     E = 6.63 10⁻³⁴ 3 10⁸/397 10⁻⁹

     E = 5.01 10⁻¹⁹ J

Let's reduce to eV

     E = 5.01 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

     E = 3.1313 eV

Let's examine the possible transitions from the initial level ni = 2

     ΔE = E_{2} - E_{n} = -3.1313

     En = 3.13 -3.4015

     E_{n} = 0.2702 eV

When examining the table we see that the level that this energy has is the level of n = 7

Part B      the transition is in the infrared

The frequency is 74 10¹² Hz

We use the Planck equation

       E = h f

       E = 6.63 10⁻³⁴ 74 10¹²

       E = 4.9062 10⁻²⁰ J

       E = 4.9062 10⁻²⁰ / 1.6 10⁻¹⁹

       E = 0.3066 eV

We look for the level with the energy difference

     ΔE = E₄- E_{n} = 0.3066

     E_{n} = 0.3066 - 0.85037

     E_{n} = -0.54376 eV

When examining the table this energy has the level n = 5, therefore from this level the transition occurs

6 0
4 years ago
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egoroff_w [7]

Answer:

The answer is b the radiation of the suns electromagnetic waves

Explanation:

I took the Quiz to.

6 0
3 years ago
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