Consider three identical metal spheres, A, B, and C. Sphere A carries a charge of +6q. Sphere B carries a charge of -q. Sphere C
1 answer:
Answer:
Part a)
Final charge on C : q = 1.875
Part b)
Ratio for A = 6 : 1.25
Ratio for B = -1 : 1.875
Ratio for C = 0
Explanation:
When two identical metal sphere are connected together then the charge on them will get equally divided on both after connecting them by conducting wire
So here we have
Step 1: We connected A and B and then separate them
so we have
Step 2: We connected A and C and then separate them
so we have
Step 3: We connected B and C and then separate them
so we have
You might be interested in
The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 * C
Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.
Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.
charge = capacitance * voltage
Q = CV
= 3 * * 15 v
= 45 * C
To learn more about capacitance here
#SPJ4