All categories

3 years ago

Bayes' theorem provides a way to transform prior probabilities into posterior probabilities. Group of answer choices True False

Mathematics

1 answer:

Dvinal [7]3 years ago

6 0

Answer:

True

Step-by-step explanation:

Bayes' theorem is indeed a way of transforming prior probabilities into posterior probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.

The prior probability in this theorem is the present understanding we possess about the possible outcome of an event based on the current understanding we have about the subject. Posterior probability on the other hand is the new understanding we have of the subject matter based on an experiment that has just been performed on it. Bayes' Theorem finds widespread application which includes the fields of science and finance. In the finance world, for example, Bayes' theorem is used to determine the probability of a debt being repaid by a debtor.

You might be interested in

A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

3 years ago

A retailer sold an electric item to a customer at a loss of 10 percent the customer purchase it for rs 25425 including 13, perce

Mashutka [201]

Answer: Rs 25,000

Step-by-step explanation:

Given

Retailer sold an electric iron to a customer at a loss of 10%

Suppose the Cost price of iron is $x$

So, selling price is $0.9x$

This price must be equal to $25425$ + VAT

$\Rightarrow 0.9x=25425-0.13(0.9x)\\\Rightarrow 0.9x+0.117x=25425\\\Rightarrow 1.017x=25425\\\Rightarrow x=\text{Rs }25,000$

Thus, the cost price is $Rs.25,000$

5 0

3 years ago

Brooke has to set up 70 chairs in equal rows for the class talent show. But, there is not room for more than 20 rows. What are t

-Dominant- [34]

5 rows of 14 chairs
7 rows of 10 chairs
Or
14 rows of 5 chairs
10 rows of 7 chairs

6 0

3 years ago

Read 2 more answers

I need help. I don't understand

ycow [4]

Add them all together

5 0

3 years ago

6x-1 + 4X+21 = 50 solve for x

emmainna [20.7K]

Answer:

x=3

Explanation:

First what you do is move x to one side and the rest of the numbers to another while changing the sign from + to - or - to + like this
6x+4x= 1+-21+50

Then you do the equation on 1 side
6x+4x=30

And then the other but add them like x is not there
10x=30
Your final result should be
X=3

3 0

3 years ago

Read 2 more answers