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timurjin [86]
3 years ago
9

Help!! plssssssssssssssssssssss

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

1.D

2.E

3.A

4.G

5.C

6.F

7.B

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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GuDViN [60]

Answer:

\frac{-5 \pm \sqrt{13} }{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}<u />

<u />

<u>Step 2: Evaluate</u>

  1. Evaluate Exponents:                    \frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}
  2. Evaluate Multiplication:               \frac{-5 \pm \sqrt{25-12} }{6}
  3. Evaluate Subtraction:                  \frac{-5 \pm \sqrt{13} }{6}
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