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podryga [215]
3 years ago
11

Dominik uses 20 grams of filling for each dumpling he makes. He has 1500 grams of dumpling filling. The grams F of filling remai

ning is a function of d, the number of dumplings Dominik makes. Write the function's formula.
Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:F=−20d+1500


Step-by-step explanation:he amount of filling used to make each dumpling is constant, so we're dealing with a linear relationship.

We could write the desired formula in slope-intercept form: F=\greenD md+\maroonD bF=md+b. In this form, \greenD mm gives us the slope of the graph of the function and \maroonD bb gives us the yy-intercept. Our goal is to find the values of \greenD mm and \maroonD bb and substitute them into this formula.

Hint #22 / 3

We know that each dumpling Dominik makes decreases the filling remaining by 2020 grams, so the slope \greenD mm is \greenD{-20}−20, and our function looks like F=\greenD{-20}d+\maroonD bF=−20d+b.

We also know that Dominik has 15001500 grams of filling initially, so the yy-intercept \maroonD{b}b is \maroonD{1500}1500.

Hint #33 / 3

Since \greenD{m}=\greenD{-20}m=−20 and \maroonD{b}=\maroonD{1500}b=1500, the desired formula is:


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eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

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3 years ago
Read 2 more answers
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Answer:

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Therefore, m∠KJN = m∠LJN

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m∠KJN = (7x - 6)

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m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = \frac{1}{2}(\angle JKN)

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