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alexdok [17]
3 years ago
15

Can the quadratic polynomial x2+kx+k have equal zeroes for some odd integer k>1

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0
No.
The only value that can be put in K that would have the same zeros would be 4 but 4 is not an odd integer. If there was an odd integer that the sum and product would be the same then it would lie on the x-axis. but only 4 fits the criteria.
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If 10 pens cost £4.00 then find the cost of 7 pens
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£4 = 400p. 400p divided by 10 is 40p, which means 40p is the price of one pen. 40p x 7 is the price of 7 pens, which is 280p.
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4 years ago
Read 2 more answers
The height of a cylinder is 10 and the area of a base is 36 pi square units. What
ollegr [7]

Answer:

1130.97336 units^3

Step-by-step explanation:

The volume of a cylinder can be found using:

v=\pi r^2h

We have the area of the base, but not the radius

a=\pi r^2

We know the area is 36\pi, so we can substitute that in for a

36\pi =\pi r^2

We want to find r, so we need to isolate it

Divide both sides by pi

36=r^2

Take the square root of both sides

6=r

Now we know the radius, and can substitute it into the volume formula, and we can substitute the height (10) in

v=\pi r^2h

v=\pi 6^210

Solve the exponent

v=\pi 36(10)

v=\pi 360

v=1130.97336

The volume is 1130.97336 units^3

6 0
4 years ago
Write .00026 as a multiple of a power of 10​
cluponka [151]

Step-by-step explanation:

0.00026 = 2.6 \times  {10}^{ - 4}  \\

3 0
3 years ago
Gina has to pay monthly installments for a period of 24 months to
madreJ [45]
It would be a lease.
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3 years ago
question 31 pts a fair six-sided die is tossed 300 times. find the expected value of the sample mean of the values obtained in t
mojhsa [17]

The expected value of the sample mean of the values obtained in these 300 tosses is 3.5

Given :

A fair six sided die is tossed 300 times

We have to find the expected value of the sample mean of the values obtained in these 300 tosses.

A dice have six sides:

In a fair dice every side has equal chance of occurrence,

Now the probability of presence of each side = 1/6

Now the expected value of the sample mean of the values obtained in these 300 tosses is given by:

E(x) = Σx P(x =x)

= 1*1/6 + 2*1/6 + 3*1/6 + 4*1/6 + 5*1/6 + 6*1/6

= 1/6 + 2/6 + 3/6 + 4/6 + 5/6 + 6/6

= 1/6 (1+2+3+4+5+6)

= 1/6 (21)

= 21/6

E(x) = 3.5

Hence, the expected value of the sample mean of the values obtained in these 300 tosses is 3.5

To know more about sample mean check the below link:

brainly.com/question/29739571

#SPJ4

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2 years ago
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