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3 years ago

A rectangular goat pasture has dimensions represented by the expressions y – 4 and 4y^2-3y+5 .Find the area of the pasture.

1 answer:

8 0

Given that the goat pasture is rectangular with the dimensions given by:
Length=(y-4) and Width=(4y^2-3y+5)
Thus the area of the pasture will be given:
Area=length*width
Area=(4y^2-3y+5)(y-4)
Area=y(4y^2-3y+5)-4(4y^2-3y+5)
Area=4y^3-19y^2+17y-20

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nirvana33 [79]

Answer:

Step-by-step explanation:

you have opposite but need to find hypotenuse so you use SOH (sine=opposite/hypotenuse)

so sin(30)= 7/a

7/sin(30)=14

Hope its right

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3 years ago

What fractional parts is this ruler divided into

algol [13]

Answer:

Based on what I can see, the answer is sixteenths.

Step-by-step explanation:

If you count every tick on the line, you can get the number sixteenths. Hope this helped :)

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2 years ago

Can you help thank youu!! will mark the first answer!!

ELEN [110]

Answer:

0.3× $10^{5}$

Step-by-step explanation:

0.3× $10^{5}$ =30000

8 0

2 years ago

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It's time for another financial calculator problem. A UCF student (who has not taken FIN 2100) decides that he really needs a la

AysviL [449]

Answer:

interest rate is 38.68 %

Step-by-step explanation:

Given data

installment = $60

time = 36 months = 36/12 = 3 years

principal = $1000

to find out

interest rate

Solution

we know student pay $60 for 36 months

so he pay total = 60 × 36 = 2160

total amount pay by student = $ 2160

so we can find interest rate by given formula

rate = (1/time)(amount/Principal - 1)

put the value time amount and principal here

rate = (1/3)(2160/1000 - 1)

rate = 0.386667

interest rate is 38.68 %

5 0

3 years ago

Draw at least six different sized rectangles that have an area of 64 square units

olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

$A=x*y$

$A=64\ units^{2}$

$x*y=64$ --------> equation 1

let's assume different values of x to get the different values of y

case 1) For x=64 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/64$

$y=1\ units$

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

case 2) For x=32 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/32$

$y=2\ units$

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

case 3) For x=16 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/16$

$y=4\ units$

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

case 4) For x=30 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/30$

$y=\frac{32}{15} =2\frac{2}{15} \ units$

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

case 5) For x=40 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/40$

$y=1.60\ units$

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

case 6) For x=60 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/60$

$y=\frac{16}{15} =1\frac{1}{15} \ units$

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

3 0

3 years ago