Question

2x-3/x devided by 7/x^2

Answer 1

Answer:

$\frac{2x^2-3x}{7}$

Step-by-step explanation:

$\frac{2x-3}{x}$ ÷  $\frac{7}{x^2}$

=> $\frac{2x-3}{x}$ × $\frac{x^2}{7}$

=> $\frac{2x-3}{7}$ × $\frac{x^2}{x}$

=>$\frac{x(2x-3)}{7}$

=> $\frac{2x^2-3x}{7}$