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3 years ago

2x-3/x devided by 7/x^2

Mathematics

1 answer:

Sergio039 [100]3 years ago

4 0

Answer:

$\frac{2x^2-3x}{7}$

Step-by-step explanation:

$\frac{2x-3}{x}$ ÷ $\frac{7}{x^2}$

=> $\frac{2x-3}{x}$ × $\frac{x^2}{7}$

=> $\frac{2x-3}{7}$ × $\frac{x^2}{x}$

=> $\frac{x(2x-3)}{7}$

=> $\frac{2x^2-3x}{7}$

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