Does anyone know what 5790.261483 is rounded to the nearest penny? thanks.

Mademuasel [1]

Answer and Step-by-step explanation:

These two terms (pronounced as Sine and Cosine) are used to solve for the sides and angles of a triangle in Trigonometry.

They are functions revealing the shape of a right triangle.

Sine is a trigonometric function of an angle. The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle, to the length of the longest side of the triangle.

Cosine is also a trigonometric function of an angle. The cosine of an angle is the relation of the length of the side that is adjacent that angle, to the length of the longest side of the triangle.

#teamtrees #PAW (Plant And Water)

8 0

3 years ago

Derek says that the quotient of -2/7 divided by -2/21 is -1/3. Part A: What is the correct quotient? Part B: What mistake did De

Thepotemich [5.8K]

Answer:

The correct quotient is 3.

I think Derek has mistaken to divide $-\frac{2}{21}$ by $\frac{2}{7}$ .

Step-by-step explanation:

We have to check the quotient of $(-\frac{2}{7}) \textrm{ divided by }(-\frac{2}{21})$ .

Part A:

Now, $(-\frac{2}{7}) \textrm{ divided by }(-\frac{2}{21})$ .

= $\frac{-\frac{2}{7} }{-\frac{2}{21} } =3$

So, the correct quotient is 3.

Part B:

Derek says that the quotient is $-\frac{1}{3}$ .

So, I think Derek has mistaken to divide $-\frac{2}{21}$ by $\frac{2}{7}$ . (Answer)

8 0

3 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

Find the slope using the following two points (19.3) and (20,3)

Sidana [21]

The slope is 0 I’m pretty sure because it is a horizontal line, if it was a vertical line it would be undefined

4 0

3 years ago

-6(x+7)=-4x-2 How many solutions does it have

geniusboy [140]

Answer:

Equation have Unique solution i.e $x=-20$

Step-by-step explanation:

Given Equation:

$-6(x+7)=-4x-2$

Solving the Equation for 'x'.

$-6(x)-6(7)=-4x-2\\\\-6x-42=-4x-2$

Adding ' $4x$ ' both sides:

$-6x+4x-42=-4x+4x-2\\\\-6x+4x-42=-2\\\\-2x-42=-2$

Adding '42' both sides:

$-2x-42+42=-2+42\\\\-2x=40$

$x=\frac{40}{-2} \\\\x=-20$

The equation have Unique solution with the value of $x=-20$

6 0

3 years ago