Which answer correct estimates the product of 3.09 × 304.87? A. about 9.0 B. about 9.9 C. about 90 D. about 900

2 answers:

7 0

The answer is D. about 900. 3.09 x 304.87 =942.0483. so rounded
by the tens you would get about 900

4 0

D.)about 900. reason being it equals 942.0483, rounding to 942.

You might be interested in

blagie [28]

Answer:

B) Inside the nucleus of an atom are protons and electrons.

Explanation:

Inside the nucleus of an atom are protons and neutrons. Electrons orbit (kind of?) away from the nucleus.

8 0

2 years ago

Lyrx [107]

Im guessing he answered 30 correct, let me know if im correct

3 0

3 years ago

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$