Answer:
The margin of error is of 0.01.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of .
That is z with a pvalue of , so Z = 1.037.
The margin of error is of:
In which is the standard deviation of the population and n is the size of the sample.
Standard deviation was 0.21.
This means that
Sample of 450:
This means that
What is the margin of error, assuming a 70% confidence level, to the nearest hundredth?
The margin of error is of 0.01.
a negative times a negative is a positive answer so both 5 *6 and -5 *-6 = 30
the answer is C
Using the normal distribution, it is found that 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of full term newborn female infants with a head circumference between 31 cm and 36 cm is the <u>p-value of Z when X = 36 subtracted by the p-value of Z when X = 31</u>, hence:
X = 36:
Z = 1.83
Z = 1.83 has a p-value of 0.9664.
X = 31:
Z = -2.33
Z = -2.33 has a p-value of 0.0099.
0.9664 - 0.0099 = 0.9565.
0.9565 = 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
More can be learned about the normal distribution at brainly.com/question/24537145
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If the question is 5m^2 the answer is 80. And if the question is 5m2 then it is 40