Write the below algebraic expression in words 3x+ (x)=10 2
1 answer:
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To find the number of terms in the arithmetic sequence, we need to use the formula
where
is the nth number, 
is the first number, n is the number of terms and d is the difference of the two consecutive numbers.
7373 = 1313 + (n - 1)(303)
7373 = 1313 + 303n - 303
7373 = 1010 + 303n
7373 - 1010 = 303n
6363 = 303n
6363 ÷ 303 = n
n = 21
Therefore, there are 21 terms in the arithmetic sequence given.
where
7373 = 1313 + (n - 1)(303)
7373 = 1313 + 303n - 303
7373 = 1010 + 303n
7373 - 1010 = 303n
6363 = 303n
6363 ÷ 303 = n
n = 21
Therefore, there are 21 terms in the arithmetic sequence given.