Amount in compound interest = p(1 + r/t)^nt where p is the initial
deposit, r = rate, t = number of compunding in a period and n = period.
Here,
Amount after 6 months (0.5 year) = 1,950(1 + (4.25/100)/4)^(0.5 x 4) = 1,950(1 +
0.0425/4)^2 = 1,950(1 + 0.010625)^2 = 1,950(1.010625)^2 = 1,950(1.0213629) =
$1,991.66
Compound interest = Amount - principal (initial deposit) = $1,991.66 - $1,950 = $41.66
P(LC / S) = P(S intersect LC) / P(S)
P(S intersect LC) = P(S)*P(LC / S) = 0.19 * 0.158 = 0.03
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
x = 152.6
Step-by-step explanation:
180 - 27.4 there you go
<h3>
Answer: (-3, 0)</h3>
Explanation:
Point N is at (1,3)
We apply the rule 
which will translate the point 4 units to the left and 3 units down.
The old x coordinate x = 1 becomes x-4 = 1-4 = -3
The old y coordinate y = 3 becomes y-3 = 3-3 = 0
The point N(1,3) moves to N ' (-3, 0)
