Combinatorial Enumeration. That whole class was a rollercoaster ride of mind-blowing generating functions to prove crazy things. The exam had ridiculous questions like 'count the number of cactus trees with n vertices such that etc etc etc' and you'd do three pages of terrible terrible sums and algebra. Then your final answer would be something beautiful like n/2 and you'd breath a sigh of relief and thank the math gods.
We have 3 white balls in the first urn out of 9. That means we have a 1 in 3 chance at picking the white ball in the first urn.
Now, we have a 3 in 11 chance at picking the white ball in the second urn.
Since, we want them simultaneously, we need to multiply them.
1/3 × 3/11 = 1/11 chance
Answer:
please mention the statement
without that I can't help
have a beautiful day
Answer:
it's B, C, and D
Step-by-step explanation:
A. w ⋅ 462 = 16 1/2
not A
w * a ≠ l
B. 16 1/2 ⋅ w = 462
is B
l * w = a
C. 462 ÷ 16 1/2 = w
is C
a / l = w
D. 462 ÷ w = 16 1/2
is D
a / w = l
E. 16 1/2 ⋅ 462 = w
not E
l * a ≠ w
Answer:
C
Step-by-step explanation:
