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3 years ago

PLEASE HELP ME I WILL GIVE BRAINLIEST

Mathematics

2 answers:

damaskus [11]3 years ago

8 0

2(3.14)5. Circumference formula = 2 x 3.14 x radius of circle

Artist 52 [7]3 years ago

7 0

First and the third one
Hope that helped and sorry if I do get it wrong

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Simplify the expression (10x + 12 - 3x) by combining like terms.

Misha Larkins [42]

Answer:

7x+12

Step-by-step explanation:

You do 10x-3x since they both have the x variable they can be combined to make 7x and the 12 is left alone.

4 0

3 years ago

Read 2 more answers

denpristay [2]

Answer:

15n=135

Step-by-step explanation:

first, you need to know how much of the total amount is the money needed for soccer balls, to find this you take the amount of a soccer ball and multiple it by the amount of people

14×15=210

then you subtract that from the total amount to get the amount spent on jerseys.

345-210=135

to get the amount of each jersey you take 135 and divide by the amount of people

135÷15=9

4 0

3 years ago

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$