b = 1/6
Explanation:
3x-y=4 ...1st equation
Rewriting in slope- intercept form:
y = 3x - 4
2y+4bx=1
Rewriting in slope- intercept form:
2y = -4bx + 1
y = -4bx/2 + 1/2
Equation of line: y = mx + c
where m = slope, c = intercept
For a line to be perpendicular to another, the slope of one will be the negative reciprocal of the slope of another.
Slope of the 1st equation = 3
m = 3
reciprocal of 3 = 1/3
negative reciprocal of 3 = -1/3
Slope of the 2nd equation = -4b/2
we equate both slope:
negative reciprocal of 3 = -4b/2
-1/3 = -4b/2
cross multiply:
-1(2) = 3(-4b)
-2 = -12b
Divide both sides by -12:
-2/-12 = -12b/-12
b = 1/6
Hence, the value of b that makes the lines perpendicular is 1/6
440 degrees in 32 seconds
8X4=32
110X4=440
Answer:
thousands place?
Step-by-step explanation:
169.866666667
9 in tenths place
6 in hundredths place
1 is in the thousands place
Answer:
1. 13 or -13
2. -5 < y < -3
3. 6 or -6
4. 1/8 or -1/8
Step-by-step explanation:
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |x|
For the Negative case we'll use -(x)
For the Positive case we'll use (x)
Step 3 :
Solve the Negative Case
-(x) = 13
Multiply
-x = 13
Multiply both sides by (-1)
x = -13
Which is the solution for the Negative Case
Step 4 :
Solve the Positive Case
(x) = 13
Which is the solution for the Positive Case
Step 5 :
Wrap up the solution
x=-13
x=13
But for the case of question (2) its a different pattern..
Since this is a "less than" absolute-value inequality, my first step is to clear the absolute value according to the "less than" pattern. Then I'll solve the linear inequality.
| y + 4 | < 1
–1 < y + 4 < 1
This is the pattern for "less than". Continuing, I'll subtract 3 from all three "sides" of the inequality:
–1 – 4 < y + 4 - 4 < 1 – 4
–5 < y < -3

The solution to the original absolute-value inequality, | y + 4 | < 1 , is the interval:

Answer:
A. 2
Step-by-step explanation:
The computation is shown below:
As we know that
The Volume of a right circular cylinder is

Here r is the radius
And h is the height
Now it is mentioned that the height of the right circular cylinder P is double to the height of the right circular cylinder Q
Now let us assume h be the height of cylinder p
And, H be the height of cylinder Q
So the equation is
h = 2H ........(1)
Also
The radius of both the cylinders would be the similar length
So
we assume the r be the radius of both cylinders
Now
The Volume of cylinder Q = 
And for P it is 
Now substitute equation 1

Hence, the correct option is A.