Answer:
12/4 i really hope this helps i took the test and got a 100
Step-by-step explanation:
Let ABC the vertices of the EQUILATERAL triangle inscribed in the circle centered in O & with R as radius (sketch it to better understand)
Join OA & OB so that to calculate the area of sector BOA
Mesure Angle C = 1/2 mes Arc AB, but C =60° , then Arc AB = 120°
So the central angle AOB = mes ARC OAB = 120°
The area of a sector = mes angle BOA x R² (mind you angle should be in radian) Angle BOA = 120°or 2π/3 (in radian) the Area Sect = (2π/3).R²
Answer:
(H)^2=(B)^2 +(P)^2
(13cm)^2=(12cm)^2 +(P)^2
169cm^2=144cm^2 +(P)^2
169cm^2-144cm^2 =(P)^2
25cm^2 = (P)^2
Now taking square root on both sides
5cm = P
Step-by-step explanation:
Answer:
20.8333...
Step-by-step explanation:
1 1/4=5/4
(5/4)/3=x/50
cross product
3*x=(5/4)(50)
3x=250/4
3x=62.5
x=62.5/3
x=20.8333...
Answer:
2,2
Step-by-step explanation:
6+7+8+0×0=0-6-6-6-6+7+7+8+4×0=0
