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Alexus [3.1K]
3 years ago
8

Answe these two, please show your work

Mathematics
2 answers:
I am Lyosha [343]3 years ago
5 0

8+5x(-4)-(-6+-2)

13 x -4 - -6+-2

-52 - -6 + -2

58 + -2

-56

Colt1911 [192]3 years ago
4 0
8+7.(-5)-(-2+9)= -34 and 8+5.(-4)-(-6+2)= -8
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Calculate an estimate of a square root of 119 + 120i
uysha [10]

Answer:

Step-by-step explanation:

Given

z=119+120 i

Let \sqrt{119+120 i}=p+iq

Squaring both sides

119+120 i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

119=p^2-q^2-----------1

comparing Im(LHS)=Im(RHS)

120=2pq

q=\frac{60}{p}

Substitute q in 1

119=p^2-(\frac{60}{p})^2

p^4-119p^2-(68)^2=0

Let x=p^2

x^2-119x-4624=0

x=frac{119\pm \sqrt{119^2+4\times 4624}}{2}

x=\frac{119\pm 180.71}{2}

we take only Positive value because p^2=x

x=149.85

p^2=149.85

thus p=\pm 12.24

q=\mp 4.90

thus \sqrt{119+120 i}=\pm (12.24+i 4.90)

6 0
4 years ago
Find the value of x and y
GarryVolchara [31]

Answer:

x = 60

y = 30

Step-by-step explanation:

We know that all triangles' interior angles combined must have a sum of 180.

Since the triangle on the left is a equilateral triangle, we know that each angle is equal to 60.

Since we already know that the sum of the two angles in the top right is 90 (shown by the right angle symbol) and we know that the angle that isn't y is equal to 60, we must do the following step:

90 - 60 = y

90 - 60 = 30

y = 30

Now that we know the value of y, it's time to find the value of x.

We know that y = 30 and that the angle in the bottom right is equal to 90 (shown by right angle symbol).

Since all triangles' interior angles combined must have a sum of 180 and we already know that one angle is equal to 30 and the other is equal to 90, we must do the following:

180 - (90 + y) = x

180 - (90 + 30) = x

180 - 120 = x

180 - 120 = 60

x = 60

This gives us the answers y = 30 and x = 60

7 0
3 years ago
What two numbers multiply to 44 and add up to 12?
djverab [1.8K]
This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.

let the two numbers be x and y.

Multiply to 44.      x*y = 44 ..........(a)

Add up to 12.      x + y = 12 .........(b)

From (b)

y = 12 - x .......(c)

Substitute (c) into (a)

x*y = 44

x*(12 - x) = 44   

12x - x² = 44

-x² + 12x = 44

-x² + 12x - 44 = 0.       

Multiply both sides by -1

-1(-x² + 12x - 44) = -1*0

x² - 12x + 44 = 0.   

This does not look factorizable, so let us just use quadratic formula

comparing to ax² + bx + c = 0, x² - 12x + 44 = 0,  a = 1, b = -12, c = 44 

x = (-b + √(b² - 4ac)) /2a   or (-b - √(b² - 4ac)) /2a


x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)    

x = (12 + √(144 - 176) )/ 2

x = (12 + √-32 )/ 2

√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2

Where i is a complex number.  Note the equation has two values. We shall include the second, that has negative sign before the square root.

x = (12 + √-32 )/ 2      or     (12 - √-32 )/ 2   

x = (12 + 4i√2 )/ 2              (12 - 4i√2 )/ 2 

x = 12/2 + (4i√2)/2                12/2 - (4i√2)/2

x = 6 + 2i√2            or         6 - 2i√2

Recall equation (c):

y = 12 - x, When x = 6 + 2i√2,  y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2

When x = 6 - 2i√2,  y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2


x = 6 + 2i√2,  y = 6 - 2i√2

x = 6 - 2i√2,  y = 6 + 2i√2

Therefore the two numbers that multiply to 44 and add up to 12 are:

6 + 2i√2 and 6 - 2i√2
8 0
3 years ago
Read 2 more answers
If h is 36in, w is 28in, and A is 6112in to the second power, what is the length of the box
OlgaM077 [116]
The length of the box would be 12288.
5 0
4 years ago
Someone please help. I have done 60% progress for math on this online school called Acellus. And I’d I don’t make it to 70% befo
harkovskaia [24]

Answer:

hindi kopo maintindihan naliliyo po ako nyan

4 0
3 years ago
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