The question is incomplete:
Ava makes bead necklaces. She has a total of 6048 beads. Each necklace has 24 beads. Her friend maria says that the greatest number of necklace she can make with the beads is 162. Marias. Work is shown here. Explain why Maria is incorrect and how she can find the correct answer.
Answer:
Maria is incorrect because when you divide the number of beads by the beads in each necklace, you find that she can make 252 necklaces.
Step-by-step explanation:
You can find the number of necklaces Avan can make by dividing the number of beads she has by the amount in each necklace:
6048/24=252
According to this, you can say that Maria is incorrect because when you divide the number of beads by the beads in each necklace, you find that she can make 252 necklaces.
Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.
Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.
_____
In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
R + J = total speed
R - J = difference speed
Adding these two equations, we have
2R = (total speed + difference speed)
R = (total speed + difference speed)2 . . . . . as computed above
Answer:
-2y +2
Step-by-step explanation:
(x - y + 1) - (x + y - 1)
Distribute the minus sign
(x - y + 1) - x - y + 1
Combine like terms
x-x -y-y +1+1
-2y +2
Answer:
3/2
Step-by-step explanation:
If you want to get the coefficient of x to be 1, you multiply by the reciprocal of the coefficient. The reciprocal is 3/2, so you multiple by 3/2
Answer:
Step-by-step explanation:
for c- start at 0, go to the left and stop right above the zero. do not put a point. then go down and stop in between -2 and -3. put a point
For D- start at zero. go to the right and stop between the four and the end of the line. Do not put a point. Then go up one box. put a point.
