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4 years ago

What is the perimeter of the rectangle in the coordinate plane

Mathematics

2 answers:

DochEvi [55]4 years ago

7 0

Perimeter is when you add the sides. The top is 4 and so is the bottom. = 8

One side is 11 and so is the other = 22

8+22= 30

Leya [2.2K]4 years ago

3 0

Answer:

C.) 30 units

Step-by-step explanation:

top and bottom sides are 4, left and right sides are 11, add

4+4 = 8

11+11=22

22+8=30

(sorry My other answer was wrong, I calculated Area, not Premeter.

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ladessa [460]

This question requires us to use the cosine rule:

a^2 = b^2 + c^2 - 2bc*cos(A),

where A is the included angle between sides b and c, and a is the side of the triangle opposite to the angle.

In the context of the question, a is the length of the tunnel (let's call this t), b is 6 km, c is 7 km and A is 29°.

Given the values in the question and those we defined, we can rewrite the equation for the cosine rule as:

t^2 = 6^2 + 7^2 - 2(6)(7)cos(29)

Now, evaluating this we get:

t^2 = 36 + 49 - 84cos(29)

t^2 = 85 - 84cos(29)

t = sq.root (85 - 84cos(29))

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4 years ago

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Jake has $11 to spend at a book fair. Each new book is $4 and he has a $5 coupon that he wants to use. How many new books (b) ca

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Step-by-step explanation:

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3 years ago

There are 7 red balls, 9 black balls and 3 white balls in a box. What is the chance to draw two black balls?

MrRissso [65]

You have a chance of 1/2 of getting a black ball. Good luck

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3 years ago

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Simplify the expression: 7d +12-14d-3

Akimi4 [234]

Group like terms
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3 years ago

Carlos and Kristin are selling wrapping paper for a school fundraiser. Customers can buy rolls of

goldfiish [28.3K]

The cost of one roll of plain wrapping paper is $8 and one roll of holiday wrapping paper is $14.

Step-by-step explanation:

Let,

Cost of one plain wrapping paper = x

Cost of one holiday wrapping paper = y

According to given statement;

6x+y=62 Eqn 1

3x+10y=164 Eqn 2

Multiplying Eqn 2 by 2

$2(3x+10y=164)\\6x+20y=328\ \ \ Eqn\ 3$

Subtracting Eqn 1 from Eqn 3

$(6x+20y)-(6x+y)=328-62\\6x+20y-6x-y=266\\19y=266$

Dividing both sides by 19

$\frac{19y}{19}=\frac{266}{19}\\y=14$

Putting y = 14 in Eqn 1

$6x+14=62\\6x=62-14\\6x=48$

Dividing both sides by 6

$\frac{6x}{6}=\frac{48}{6}\\x=8$

The cost of one roll of plain wrapping paper is $8 and one roll of holiday wrapping paper is $14.

Keywords: linear equation, elimination method

Learn more about linear equations at:

#LearnwithBrainly

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