Question

Q # 11. please help to resolve

Answer 1

We know the following statements regarding the box:

1. The box is rectangular
2. It's twice as long as it is wide
3. The height of the box is 3 feet less than the width 
4. x: feet wide

So we can apply a mathematical language to solve this problem. The volume of a rectangular box can be find by:

$V=W\times L\times H \\ \\ where \\ \\ W:Width \\ L:Length \\ H:Height$

But we also know that:

$W=x$

And the box is twice as long as it is wide:

$L=2x$

The height of the box is 3 feet less than the width is given by:

$H=x-3$

So combining these results:

$V=x(2x)(x-3) \\ \therefore V=2x^2(x-3) \\ \therefore \boxed{V=2x^3-6x^2}$

The right answer is B