3x+17+5=7x+10
3x+22=7x+10
3x-7x=10-22
-4x-=-12
4x=12
X= 12/4
X=3
Answer:
Yes
Step-by-step explanation:
Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.
When both machines work for 20 minutes
Machine A would produce = 
widget and
Machine B would produce = 
widgets
So we can say that Machine A would produce more widgets than Machine N at that time.
Answer is Yes
Answer:
8.66214 x 10^11
Step-by-step explanation:
question may ask to round, so the answer may be simplified to 9 x 10^11
Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
