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Mumz [18]
3 years ago
6

Which two numbers have a least common multiple of 48?

Mathematics
1 answer:
tekilochka [14]3 years ago
6 0
While neither 9 nor 8 are prime numbers, the factors of 9 are 3*3<span> and of 8 are 2*2*2. Since they share no factors in common, their product will be the least common multiple. (Multiples of 9 are 18, 27, </span>36<span>, 45, 54, 63, and 72; Multiples of 8 are </span>16<span>, </span>24,32<span>, </span>40<span>, 48, </span>56<span>, </span>64<span>, and 72).  

This is sited on google! </span>
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pishuonlain [190]

Answer:

Step-by-step explanation:

First factor the second binomial

38^9 - 38^8 = 38^9 (38 - 1 ) = 38^9(37)

So there's your 37. This whole expression is divisible by 37

Now do the first  binomial

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That first term is going to cause a bit of trouble showing that 36^4 * 6 = 6^9

6(36^4) = 6(6^2)^4 = 6^1 * 6^8 = 6^9

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3 years ago
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8 0
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