Question

A ship is sailing on the sea. It travels 50 miles at 60° to the horizontal. Then the ship travels 90 miles at 30° to the horizontal
before coming to a stop. How many miles North has the ship travel?
A)
25+ 4573
B)
25V3+45
D)
70
E)
140

Answer 1

Answer:

$(25\sqrt{3}+45)\ miles$

Step-by-step explanation:

we know that

The total vertical distance (total miles North) traveled is equal to

$d=50sin(60^o)+90sin(30^o)$

Remember that

$sin(60^o)=\frac{\sqrt{3}}{2}$

$sin(30^o)=\frac{1}{2}$

substitute

$d=50(\frac{\sqrt{3}}{2})+90(\frac{1}{2})$

$d=(25\sqrt{3}+45)\ miles$