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Elena-2011 [213]
3 years ago
10

A ship is sailing on the sea. It travels 50 miles at 60° to the horizontal. Then the ship travels 90 miles at 30° to the horizon

tal
before coming to a stop. How many miles North has the ship travel?
A)
25+ 4573
B)
25V3+45
D)
70
E)
140
Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

(25\sqrt{3}+45)\ miles

Step-by-step explanation:

we know that

The total vertical distance (total miles North) traveled is equal to

d=50sin(60^o)+90sin(30^o)

Remember that

sin(60^o)=\frac{\sqrt{3}}{2}

sin(30^o)=\frac{1}{2}

substitute

d=50(\frac{\sqrt{3}}{2})+90(\frac{1}{2})

d=(25\sqrt{3}+45)\ miles

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23.7

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23.69
23.71

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Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).
kirill115 [55]

Answer:

The Correct option is Last one y=-4x-4

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line y=-4x-3 is y=-4x-4

Step-by-step explanation:

Given:

y=-4x-3

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

y=-4x-3 ..........Given

Comparing with Slope-Intercept form,  

y=mx+c

Where m =slope  

We get

Slope = m = -4

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

(y-y_{1})=m(x-x_{1})

Substituting the points and so we will get the required equation of the line,

(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line y=-4x-3 is y=-4x-4

8 0
3 years ago
Helping my daughter with ratio table homework. I do not understand the concept of the tables. Here is one of her questions that
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2 years ago
(Answer with steps please)
77julia77 [94]

Answer:

Step-by-step explanation:

a). Total surface area of cylinder is defined by sum of curved surface area and surface area of the top and bottom.

Total surface area = 2πrh + 2πr²

Skateboarders use a half pipe structure which are not closed at the ends.

Therefore, curved surface of the half pipe = \frac{2\pi rh}{2}

                                                                      = πrh

b). If r = 2.5 m and h = 9 m,

Curved surface area of the half pipe = π(2.5)(9)

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4 0
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