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miss Akunina [59]

3 years ago

14

you are being deal one card from a standard 52 card deck. what is the probability that you will be dealt a card other than an ac

e?

2 answers:

8090 [49]3 years ago

8 0

I love you please notice me

galben [10]3 years ago

3 0

The probability of you getting in Ace is 4/52

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Can u help me with this

Tanzania [10]

1. x^2 + x - 90

2. (x+10)(x-1)

3. x= -10 and 1

4 0

3 years ago

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Sodium is a reactive metal. chlorine is a reactive gas. these two elements combine to form a

11Alexandr11 [23.1K]

A and d seem correct to me.

b and c are definitely wrong.

8 0

3 years ago

(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

dezoksy [38]

Answer:

D

Step-by-step explanation:

literlay just count

3 0

3 years ago

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

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BRAINLIEST ASAP!!!!!!!<br><br> why is it useful to factor out the gcf first when factoring

Lelu [443]

By pulling out the common factors for each pair of terms, we can rewrite the original polynomial like this:
3x(2x + 1) + 10(2x + 1)
These two terms now have a common factor of (2x + 1). Seems like we should be able to do something with that information, don't you think? In fact, we can pull out this common factor and rewrite the polynomial again:

4 0

3 years ago