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yarga [219]
3 years ago
8

Given an actual demand this period of 61, a forecast value for this period of 58, and an alpha of 0.3, what is the experimential

smoothing forecast for the next period?
Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0

Answer:

Experimental smoothing forecast for the next period will be 58.9

Step-by-step explanation:

We have given actual demand is A_{t-1}=61

Initial forecast f_{t-1}=61 and \alpha =0.3

We have to find the experimental smoothing forecast f_t

Experimental forecast is given by

f_t=(1-\alpha )f_{t-1}+\alpha A_{t-1}=(1-0.3)\times 58+0.3\times 61=58.9

So experimental smoothing forecast for the next period will be 58.9

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A farmer fills his field proportionately with soybeans and corn. Last year he planted 200 acres of corn and 50 acres of soybeans
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Answer:

Part A)  Is a directly proportional

Part B) The constant of proportionality is k=0.25

Part C) The equation is y=0.25x

Part D) 62.5  acres of soybeans

Step-by-step explanation:

Part A) Are the number of acres of corn and the number of acres of soybeans directly proportional or inversely proportional?

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k

Let

x-----> the number of acres of corn

y---->  the number of acres of soybeans

so

y/x=k  

if the number of acres of corn increases then the number of acres of soybeans increases

if the number of acres of corn decreases then the number of acres of soybeans decreases

therefore

The relationship is a directly proportional

Part B) What is the constant of proportionality?

we have that

For x=200, y=50

substitute

y/x=k

k=50/200

k=0.25

Part C) Let x equal the number of acres of corn and y equal the number of acres of soybeans. Write an equation to show this relationship.

The linear equation that represent the direct variation is equal to

y/x=k

we have

k=0.25

substitute

y/x=0.25

y=0.25x

Part D) How many acres of soybeans can the farmer plant this year if he plants 250 acres of corn?

For x=250

Find the value of y

substitute in the linear equation the value of x and solve for y

y=0.25(250)=62.5 -----> acres of soybeans

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