Ask question

Ask question

All categories

3 years ago

15

Determine whether the integral from -3 to infinity 1/sqrt (5 - x) is divergent or convergent. If it is convergent, evaluate it.

If not, state your answer as divergent .

1 answer:

BigorU [14]3 years ago

5 0

It's divergent because 1/√(5 - <em>x</em>) is defined only for <em>x</em> < 5, which means the integral from 5 to infinity doesn't exist.

You might be interested in

Serious explination on this one with the answer guys? First to answer gets brainliest!

Alex Ar [27]

Answer:

the answer is -5x + -8x-5/2x^2-3

Step-by-step explanation:

:)

7 0

3 years ago

If 5= 5+2x then 12x= ? I’m

julsineya [31]

Answer:

12x = 0

Step-by-step explanation:

5= 5+2x

Subtract 5 from each side

5-5= 5-5+2x

0 = 2x

Multiply each side by 6

0*6 = 2x*6

0 = 12x

7 0

2 years ago

Read 2 more answers

there are 8 students at each of 4 rounds of tables in the cafeteria. there are 64 students at long tables. use the bar model to

Tomtit [17]

Step-by-step explanation:

there should be at least

4 0

3 years ago

2.4 > 2.48<br><br> true or false<br><br> pls answer thxxxxxx

grigory [225]

Answer:

FALSE

2.48 is greater than 2.4 because of the 8 at the end

3 0

3 years ago

Simplify completely x^2+4x-5/5x^2-8x+3

arlik [135]

Answer:

$\boxed{\bold{\frac{x+5}{5x-3}}}$

Explanation:

[ Step One ] Factor $\bold{x^2+4x-5}$

$\bold{x\left(x-1\right)+5\left(x-1\right)}$

[ Step Two ] Rewrite Equation

$\bold{\frac{\left(x-1\right)\left(x+5\right)}{5x^2-8x+3}}$

[ Step Three ] Factor $\bold{5x^2-8x+3}$

$\bold{\left(x-1\right)\left(x+5\right)}$

[ Step Four ] Rewrite Equation

$\bold{\frac{\left(x-1\right)\left(x+5\right)}{\left(5x-3\right)\left(x-1\right)}}$

[ Step Five ] Cancel Out Common Factor $\bold{x-1}$

$\bold{\frac{x+5}{5x-3}}$

$\boxed{\bold{Mordancy}}$

5 0

3 years ago