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4 years ago

Find TV. PLSS HELP BRAINLIEST...

Mathematics

1 answer:

Rasek [7]4 years ago

5 0

Answer:

correct answer is 7

Step-by-step explanation:

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li needs 15 pieces of string each 1/2 of a inch long. she cut a 6-inch piece of string into pieces that are 1/2 of an inch long

Firlakuza [10]

Li needs 3 more pieces, an 1 and 1/2 cut into 3 pieces.

7 0

4 years ago

Read 2 more answers

12. The equation y = 1.2x + 3 can be used to approximate the total revenue y, in millions of dollars, of the eQuest Company in y

brilliants [131]

Answer:

Step-by-step explanation:

5 0

4 years ago

Please help!posted picture of question

motikmotik

Answer:
5x⁴ + 5x³

Explanation:
We are given that:
f (x) = 5x³
g (x) = x + 1

Now, (f · g)(x) means that we will simply multiply the two functions as follows:
(f · g)(x) = f (x) · g (x)
(f · g)(x) = 5x³ (x + 1)
(f · g)(x) = 5x⁴ + 5x³

Hope this helps :)

3 0

4 years ago

Which of the following equations represents the linear relationship shown in the table below?

Sphinxa [80]

Answer:

Step-by-step explanation:

The equation is:

y = 2x + 3

Put x as 2.

y = 2(2) + 3

y = 4 + 3

y = 7

Put x as 3.

y = 2(3) + 3

y = 6 + 3

y = 9

Put x as 4.

y = 2(4) + 3

y = 8 + 3

y = 11

Put x as 5.

y = 2(5) + 3

y = 10 + 3

y = 13

6 0

3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

2 years ago