All categories

2 years ago

Which is another way to write 2 3/5?

1 answer:

4 0

$2 \frac{3}{5}$ is a mixed number.

You can rewrite it as an improper fraction by multiplying the big number (2) with the denominator (5). 2x5=10.

Then you add 10+numerator (3) = 13.

Then you put the 13 over the denominator (5). So your answer is 13/5

You might be interested in

Simplify the expression-3(b-7)

oee [108]

-3(b - 7)

Multiply -3 into the parenthesis.

= -3b + 21.

8 0

3 years ago

Read 2 more answers

If you flip a fair coin 5 times, and see 3 heads and 2 tails, what fraction of the time will you expect to see a head on the six

Margaret [11]

I hope I'm not wrong here, but B.1/2? Only because its a 50% chance

6 0

2 years ago

Please help due tomarrow good luck

amid [387]

Answer:

125+1024x

if that didn't help

Sorry;-;

5 0

3 years ago

Read 2 more answers

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$