Answer:
y = 
(x - 5)² - 2
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (5, - 2), thus
y = a(x - 5)² - 2
To find a substitute (7, 0) into the equation
0 = a(7 - 5)² - 2
0 = 4a - 2 ( add 2 to both sides )
2 = 4a ( divide both sides by 4 )
a = 
=
y = (x - 5)² - 2 ← in vertex form
If a function is even, then f(-x) = x.
If a function is odd, then f(-x) = -x.
y = x³ + x² → f(x) = x³ + x² → -f(x) = -(x³ + x²) = -x³ - x²
f(-x) = (-x)³ + (-x)² = [(-1)(x)]³ + [(-1)(x)]² = (-1)³x³ + (-1)²x²
= -1x³ + 1x² =-x³ + x²
f(-x) ≠ f(x) and f(-x) ≠ -f(x)
y = x³ + x² is not odd and not even
Answer: neither
Answer:
the answer is 150
Step-by-step explanation:
The second option. Angles 2 and 6 are corresponding angles, and 6 and 7 make a linear pair, so 2 and 7 are supplementary.
The first option doesn’t even mention angle 7, the third option doesn’t mention angle 2, and the last option doesn’t mention 7 either.
Answer:
Step-by-step explanation:
