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elena55 [62]
3 years ago
5

Question 3

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0

Answer:

13.4x - 0.5

Step-by-step explanation:

13.4x - 5.9 - 7.1 + 13.5

This may seem complicated, but it is really pretty simple once you get the hang of it.

First, you would organize your terms.

<u>13.4x</u>       - 5.9     - 7.1      + 13.5

Then you would add your like terms.

-5.9 - 7.1 + 13.5 = 0.5

So the answer to your problem would be 13.4x - 0.5

telo118 [61]3 years ago
5 0

Answer:

A........................

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2 years ago
3,425,645 rounded to the nearest hundred thousand
Ivan

Answer:

3,400,000

Step-by-step explanation:

refer to attached for reference

in our case, the digit in the hundred thousands place is the number 4.

How we round this digit depends on the digit directly to the right of it (i.e the ten-thousands place).

If the digit to the right is less than 5, then leave the digit in the hundred thousands place the same and make everything else to the right zeros.

if the digit to the right is 5 or greater, then increase the digit in the hundred thousands place by 1 and then make everything else to the right zeros.

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3 years ago
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Step-by-step explanation:

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3 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

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If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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3 years ago
Parallelogram ABCD is dilated to form parallelogram EFGH. Side BC is proportional to side CD.
egoroff_w [7]
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