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horrorfan [7]
3 years ago
7

Bytes are typically represented with a lowercase b and bits with an uppercase B. true or false

Computers and Technology
1 answer:
34kurt3 years ago
7 0

Answer:

False

Explanation:

Byte(B) is uppercase

bit(b) is lowercase

Good way to remember is that its takes 8 bits makes a byte. In other word, a byte is bigger than a bit so it makes sense that byte is uppercase.

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100 POINTS PLEASE HELP ASAP!!!!!
Elina [12.6K]

Answer: c top left corner

3 0
3 years ago
Read 2 more answers
Given the following code, what is output by the method call, mystery(6 * 8)?
Elena-2011 [213]

Answer:

i honestly don't know

Explanation:

im not smart

3 0
3 years ago
If 200.123.4.6 is a classful internet protocol (ip) address, what class is it in?
REY [17]

200.123.4.6 is a classful internet protocol (ip) address located in class C.

An IP address (internet protocol address) is a numeric representation. This numerical representation uniquely identifies a particular interface on the network.

Address in IPv4 that has a length of 32 bits. This allows a maximum of 4,294,967,296 (232) unique addresses. Addresses in IPv6 are 128-bits long, which allows for 3.4 x 1038 (2128) unique addresses.

The total usable address pools of both versions are subtracted by the various reserved addresses and other considerations.

IP addresses can also be defined as binary numbers but are usually expressed in decimal form (IPv4) or hexadecimal form (IPv6) to make it easier for humans to read and use them.

You can learn more about IP addresses here brainly.com/question/18722788

#SPJ4

4 0
1 year ago
You should process the tokens by taking the first letter of every fifth word,starting with the first word in the file. Convert t
zhenek [66]

Answer:

See explaination

Explanation:

import java.io.File;

import java.io.IOException;

import java.util.Scanner;

import java.util.StringTokenizer;

public class SecretMessage {

public static void main(String[] args)throws IOException

{

File file = new File("secret.txt");

StringBuilder stringBuilder = new StringBuilder();

String str; char ch; int numberOfTokens = 1; // Changed the count to 1 as we already consider first workd as 1

if(file.exists())

{

Scanner inFile = new Scanner(file);

StringTokenizer line = new StringTokenizer(inFile.nextLine()); // Since the secret.txt file has only one line we dont need to loop through the file

ch = line.nextToken().toUpperCase().charAt(0); // Storing the first character of first word to string builder as mentioned in problem

stringBuilder = stringBuilder.append(ch);

while(line.hasMoreTokens()) { // Looping through each token of line read using Scanner.

str= line.nextToken();

numberOfTokens += 1; // Incrementing the numberOfTokens by one.

if(numberOfTokens == 5) { // Checking if it is the fifth word

ch = str.toUpperCase().charAt(0);

stringBuilder = stringBuilder.append(ch);

numberOfTokens =0;

}

}

System.out.println("----Secret Message----"+ stringBuilder);

}

}

}

5 0
3 years ago
Write a program num2rome.cpp that converts a positive integer into the Roman number system. The Roman number system has digits I
Tom [10]

Answer:

Explanation:

#include <stdio.h>  

int main(void)  

{    

   int num, rem;

   printf("Enter a number: ");

   scanf("%d", &num);

   printf("Roman numerals: ");        

   while(num != 0)

   {

       if (num >= 1000)       // 1000 - m

       {

          printf("m");

          num -= 1000;

       }

       else if (num >= 900)   // 900 -  cm

       {

          printf("cm");

          num -= 900;

       }        

       else if (num >= 500)   // 500 - d

       {            

          printf("d");

          num -= 500;

       }

       else if (num >= 400)   // 400 -  cd

       {

          printf("cd");

          num -= 400;

       }

       else if (num >= 100)   // 100 - c

       {

          printf("c");

          num -= 100;                        

       }

       else if (num >= 90)    // 90 - xc

       {

          printf("xc");

          num -= 90;                                              

       }

       else if (num >= 50)    // 50 - l

       {

          printf("l");

          num -= 50;                                                                      

       }

       else if (num >= 40)    // 40 - xl

       {

          printf("xl");            

          num -= 40;

       }

       else if (num >= 10)    // 10 - x

       {

          printf("x");

          num -= 10;            

       }

       else if (num >= 9)     // 9 - ix

       {

          printf("ix");

          num -= 9;                          

       }

       else if (num >= 5)     // 5 - v

       {

          printf("v");

          num -= 5;                                      

       }

       else if (num >= 4)     // 4 - iv

       {

          printf("iv");

          num -= 4;                                                            

       }

       else if (num >= 1)     // 1 - i

       {

          printf("i");

          num -= 1;                                                                                    

       }

   }

   return 0;

}

8 0
2 years ago
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