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3 years ago

Add. Simplify the answer and write the answer as a mixed number if appropriate, 4 3 1

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

Step-by-step explanation:

4+3=7

7=1=8

idk if that was what you were looking for please add more information in comments and ill answer

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Which set of ordered pairs represents a linear function?

kifflom [539]

Answer:its d

Step-by-step explanation:

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3 years ago

−\frac{7}{10} ÷\frac{2}{5}

bazaltina [42]

$$ −\frac{7}{10} \div\frac{2}{5}= \frac{-7}{4} $$ . totally answer. I hope helping with this answer

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2 years ago

I know the answer but what’s the work

mina [271]

Answer:

(0.5r^2pi) + (0.5r^2pi) + (bh)

Step-by-step explanation:

All you need to do is to find the area of each shape, then add all areas together.

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3 years ago

Read 2 more answers

A school is selling tickets to their Spring theater production. Student tickets cost $6 each and non-student tickets cost $9 eac

I am Lyosha [343]

Answer:

x=137

y=525-137

y=388

Step-by-step explanation:

Let the student tickets be x

Let the geral Admission tickets be y

x+y=525

y=525-x

4x+6y=2876 (subsitute for y)

4x+6(525-x)=2876

4x+3150-6x=2876

-2x=-274

x=137

y=525-137

y=388

Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.

Paul.

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3 years ago

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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago