Answer:
2x-z=0 is the equation of the plane.
Step-by-step explanation:
Given that the plane passes through the points (1,0,2) and (-1,1,-2)
and also origin.
Hence equation of the plane passing through three points we can use
Any plane passing through 3 given points is given as
![\left[\begin{array}{ccc}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-x_1%26y-y_1%26z-z_1%5C%5Cx_2-x_1%26y_2-y_1%26z_2-z_1%5C%5Cx_3-x_1%26y_3-y_1%26z_3-z_1%5Cend%7Barray%7D%5Cright%5D%20%3D0)
Substitute the three points to get
![\left[\begin{array}{ccc}x-1&y&z-2\\-1-1&1&-2-2\\0-1&0&0-2\end{array}\right] \\=0\\(x-1)(-2) -y(4-4)+(z-2)(1) =0\\-2x+z=0\\2x-z-=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-1%26y%26z-2%5C%5C-1-1%261%26-2-2%5C%5C0-1%260%260-2%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D0%5C%5C%28x-1%29%28-2%29%20-y%284-4%29%2B%28z-2%29%281%29%20%3D0%5C%5C-2x%2Bz%3D0%5C%5C2x-z-%3D0)
2x-z=0 is the equation of the plane.
6m + 15m+ 20= 75
6m+ 15m= 75- 20
21m= 55
m= 55/21
m= 2.61
it was one important turning point in ww2 because it stopped the german advance into the soviet union
<span>y = 3x + 3
</span>y-intercept x = 0 then y = 3
<span>x-intercept y = 0 then
</span>3x + 3 = 0
3x = -3
x = -1
so answer
y = 3x + 3
The formula for finding the hypotenuse is L^2 + L^2 = H^2
Since we have both leg measurements, this should be pretty simple. First let's fit it into the formula. 29^2 + 11^2 = H^2.
841 + 121 = H^2.
962 = H^2
√962 = 31.
Hope that helps! :)
