The equation that represents the table of values is 
Step-by-step explanation:
We need to find the equation that matches the table of values.
x y
0 | 1
1 | 1/4
2 | 1/16
3 | 1/64
So, when x =0 y=1 and when x=1, y=1/4
if 
then putting x=0 we get y=1
x=1, we get y=1/4
x=2, we get y=1/16
x=3, we get y=1/64
So, the equation that represents the table of values is 
Kindly check your options, as option D should be 
Keywords: Solving Equations
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Answer:
well one similarity is that they both cross over zero and one difference is that one is going verticl and one is going up and down
Step-by-step explanation:
Answer:
I ready hope you find the answer
Step-by-step explanation:
We have the following equation:
2 (x-3) ^ 2 + 10 = 82
We must clear x.
We pass the constant terms to one side of the equation:
2 (x-3) ^ 2 = 82 - 10
2 (x-3) ^ 2 = 72
(x-3) ^ 2 = 72/2
(x-3) ^ 2 = 36
Square root to both members:
x-3 = +/- root (36)
x-3 = +/- 6
The solutions are:
x1 = 6 + 3 = 9
x2 = -6 + 3 = -3
Answer:
x1 = 9
x2 = -3
An equation will have an answer at the end like an equal sign. (Ex; 20+20=40)
An expression will NOT have an answer. (Ex; 20+20)