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jonny [76]
3 years ago
11

How is the graph y = log(2x)+3 related to the graph of y = log(x)? It is stretched horizontally by a factor of 2 and translated

up 3. It is compressed horizontally by a factor of 2 and translated up 3. It is stretched vertically by a factor of 2 and translated up 3. It is compressed vertically by a factor of 2 and translated up 3.
Mathematics
2 answers:
aev [14]3 years ago
7 0

Answer:

Option 2 - It is compressed horizontally by a factor of 2 and translated up 3.

Step-by-step explanation:

Given : The graph y=\log(2x)+3 and y=\log(x)  

To find : How does the graph of y=\log(2x)+3 related to the graph of y=\log(x)

Solution :  

The parent function be y=\log(x)

Horizontally Compressed:    

If y =f(x) , then y =f(bx) gives a horizontal compression if b>1.  

Multiplying the parent function by 2 means you are compressing it horizontally,    

i,e y=\log(x) \rightarrow \text{Horizontally compressed by 2} \rightarrow y=\log(2x)

Translated up :  

i.e, f(x)→f(x)+b  

Adding 3 means you are moving it up by 3 units  

y=\log(2x)\rightarrow \text{translated up by 3 units} \rightarrow y=\log(2x)+3  

Therefore, Option 2 is correct.

It is compressed horizontally by a factor of 2 and translated up 3.

Naya [18.7K]3 years ago
4 0

Answer:

The second choice.

Step-by-step explanation:

The  log(x)  ----> log(2x) compresses the graph horizontally by a factor of 2  .

The + 3 translates up 3.

The second choice is the correct one.

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A polynomial equation is an equation where a polynomial is set equal to zero. i.e., it is an equation formed with variables, non-negative integer exponents, and coefficients together with operations and an equal sign. It has different exponents. The highest one gives the degree of the equation. For an equation to be a polynomial equation, the variable in it should have only non-negative integer exponents. i.e., the exponents of variables should be only non-negative and they should neither be negative nor be fractions.

Now, x=3, x=2+2i and x=2-2i

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So, the polynomial equation is (x-3)(x-2-2i)(x-2+2i)=0

⇒(x-3)(x(x-2-2i)-2(x-2-2i)+2i(x-2-2i))=0

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How to find the line of reflection between two points?
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3 years ago
Point B has coordinates ​(​1,2​). The​ x-coordinate of point A is -8. The distance between point A and point B is 15 units. What
Xelga [282]

Answer:

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}} (1)

Where:

l_{AB} - Length of the line segment AB.

x_{A}, x_{B} - x-coordinates of points A and B.

y_{A}, y_{B} - y-coordinates of points A and B.

If we know that l_{AB} = 15, x_{A} = -8, x_{B} = 1 and y_{B} = 2, then the possible coordinates of point A is:

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(2-y_{A})^{2} = 144

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There are two possible solutions:

1) 2-y_{A} = -12

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The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

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3 years ago
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borishaifa [10]

Answer:

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3 years ago
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