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boyakko [2]
3 years ago
13

How is confidence levels determined?

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0
That's the answer for how is confidence levels determined

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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
Foot pieces you can cut from 5 feet of
Rzqust [24]

Answer:

1p = r

Step-by-step explanation:

You are asking how many 1-foot pieces you can make out of a 5 foot piece of ribbon. You are asking for an equation.

p = the # of pieces

r = the amount of ribbon

So lets try the equation:

1p   = r

1(4) = r

1*4 = 4

4    = r

<h2><u>PLEASE MARK BRAINLIEST!  </u></h2>
7 0
3 years ago
What is 1/3 + 1/2?.......
Virty [35]

Answer:

5/6

Step-by-step explanation:

1/3 + 1/2 = 5/6

3 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK WILL MARK BRAINLIEST.
ioda

Answer:

4.57

Step-by-step explanation:

7 can go into 32 4 times but your remainder is going to be 5

5 0
3 years ago
A group of 9 friends went bowling. Each person pays the same amount to bowl several games and a $3 fee to rent
ruslelena [56]

Answer: Each friend would pay $15.

3 0
3 years ago
Read 2 more answers
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