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iragen [17]
3 years ago
15

Please don't include the answer, just tell me the process!

Mathematics
1 answer:
iragen [17]3 years ago
8 0
It would probably help you if you drew the situation.  First realize that the length of the rope is larger than one of the dimensions.  If you allow the rope to line up with the side of larger dimension it can only sweep out an arc until it touches the opposite side.

The angle swept out can be found by realizing that sina=smaller dimension / length of rope  in this case:

sina=smaller dimension/ rope length

a=arcsin(smaller dimension/ rope length)

So the sector area is:

A=p(rope length)^2(a/360)

What remains other than the sector area a triangle with a width of the smaller dimension and a height of h=√(rope^2-width^2)

The area of this triangle is just: A=(w/2)*(√(rope^2-width^2))

Then you just add the sector area to the triangle area and you will have the area the tiger can access.
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2/3j=8 HURRY UP I HAVE A QUIZ
ycow [4]

Answer:

J=12

Step-by-step explanation:

(2/3)*j = 8 // - 8

(2/3)*j-8 = 0

2/3*j-8 = 0 // + 8

2/3*j = 8 // : 2/3

j = 8/2/3

j = 12

5 0
4 years ago
1/2 Of the class has blonde hair and 1/4 the class has black hair.1/4 of the class has brown hair If there are 32 kids in the cl
Mariulka [41]

Answer:

Step-by-step explanation:

so there is 32 kids....1/2 are blonde, 1/4 have black hair, 1/4 have brown hair

1/2(32) = 32/2 = 16 are blonde

1/4(32) = 32/4 = 8 have black hair

1/4(32) = 32/4 = 8 have brown hair

6 0
3 years ago
When BA=10 ft, find the area of the region that is NOT shaded. Round to the nearest whole number. (reply so i can draw it out, p
nexus9112 [7]
The area of the region that is not shaded in the diagram is determined through the following solution:

<span>A = <span>(1 − (<span><span>60°/</span><span>360°</span></span>)*</span>π) * (10 ft ) ^<span>2</span></span> <span>A = <span>56*</span>π*100 [<span>ft2</span>]</span> <span><span>A = <span>250/3 </span>π [<span>ft2</span>]
A = 262 [ft2]</span></span>
5 0
3 years ago
Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi
Strike441 [17]

Answer:

x(t) = –5 + 6t; y(t) = 3 – 9t

Step-by-step explanation:

6 0
3 years ago
Please help me i need help pls
OverLord2011 [107]

Answer:

see explanation

Step-by-step explanation:

(b)

30n - 12 ( factor out the gcf 6 from each term )

= 6(5n - 2) ← in factored form

(c)

6x + 9y ( factor out the gcf 3 from each term )

= 3(2x + 3y) ← in factored form

6 0
3 years ago
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