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horrorfan [7]
3 years ago
10

Using column b row 4, find the intersection of lombard street and larkin street. imagine you are in a car: head east on lombard

street three blocks, then south two blocks, and make a left. what is the first intersection you will cross?
Mathematics
1 answer:
nirvana33 [79]3 years ago
3 0
<span>Taylor Street.
   I am assuming that the Lombard street is the famous Lombard street in San Francisco, California. With that assumption, after going East 3 blocks, you'll reach the intersection of Lombard and Jones. After going south 2 blocks, you'll reach the intersection of Jones and Filbert. Finally, after turning left and going 1 block, the first intersection will be Taylor Street.</span>
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WARRIOR [948]

Step-by-step explanation:

You have to use logarithms.

1) a = log_3 (1/27) = -log_3 (27) = -3

2) b = log_3 (9 * 3^(1/2)) = log_3 (3 ^ {5/2}) = 5/2

3) c = -log_3 (sqrt3) = -1/2

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A trapezoidal prism undergoes a dilation. The surface area of the pre-image is 35 m². The surface area of the image is 315 m². T
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The original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

<h3>How does dilation affect length, area, and volume of an object?</h3>

Suppose a figure (pre image) is dilated (dilated image) by scale factor of k.

So, if a side of the figure is of length L units, and that of its similar figure is of M units, then:

<u><em>L = k × M</em></u>

where 'k' will be called as scale factor.

The linear things grow linearly like length, height etc.

The quantities which are squares or multiple of linear things twice grow by square of scale factor. Thus, we need to multiply or divide by <u><em>k²</em></u><em> </em>to get each other corresponding quantity from their similar figures' quantities.

<u><em>So </em></u><u><em>area </em></u><u><em>of </em></u><u><em>first figure </em></u><u><em>= k² × area of second figure</em></u>

Similarly,

<u><em>Volume </em></u><u><em>of first figure = k³ × volume of second figure.</em></u>

It is because we will need to multiply 3 linear quantities to get volume, which results in k getting multiplied 3 times, thus, cubed.

For this case, we're given that;

  • Surface area of pre-image = 35 m²
  • Surface area of dilated image = 315 m²
  • Height of pre-image = 5.8 m
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Let the scale fator of dilation be k.

Then:

<u><em>So area of pre-image = k² × area of dilated image</em></u>

Thus, we get:

35 = k^2 \times 315\\\\k = \sqrt{\dfrac{35}{315}} = 1/3

(took positive root as scaling is done by non-negative factors as only magnitude matters mostly)

Thus, we get:

Height of pre-image = (1/3) × Height of dilated image (say h)

5.8 = (1/3) \times h\\h = 3 \times 5.8 = 17.4 \rm \: m

Thus, the original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

Learn more about dilation here:

brainly.com/question/3266920

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Answer: 8a

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