The parabola divises the plan into 2 parts. Part 1 composes the point A, part 2 composes the points C, D, F.
+ All the points (x;y) satisfies: -y^2+x=-4 is on the <span>parabola.
</span>+ All the points (x;y) satisfies: -y^2+x< -4 is in part 1.
+ All the points (x;y) satisfies: -y^2+x> -4 is in part 2<span>.
And for the question: "</span><span>Which of the points satisfy the inequality, -y^2+x<-4"
</span>we have the answer: A and E
Step-by-step explanation:
(f+g)(x) = f(x) + g(x)
= x/2-3 + 4x²+x+4
= ..........
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The answer is B(11, 2sqrt(12) )
proof
the main equation of the circle is (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center
so if the center is the origin, it is O(0,0), and the equation becomes
<span> (x)²+(y)²=R²
</span>and the circle passes through the point (-5,2) so we can write
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13
and for <span>B(11, 2sqrt(12) ) </span>11²+ (2sqrt(12))²= 121 + 48= 169= 13
it is checked.
Answer:
VII,V,IV,VI
Step-by-step explanation:
