Answer:
Step-by-step explanation:
(a+b)^2=a^(2)+2ab+b^(2)
(a-b)^2=a^(2)-2ab+b^(2)
13)
(x+2)^(2)-(x-1)^2
x^(2)+4x+4-(x^(2)-2x+1)
x^(2)+4x+4-x^(2)+2x-1
6x+3
15)
(x+5)^(2)-(x+1)^2
x^(2)+10x+25-(x^(2)+2x+1)
x^(2)+10x+25-x^(2)-2x-1
8x+24
I will create a set of arbitrary constants (x1,y1) (x2,y2)
slope = y2-y1/x2-x1
y = (y2-y1/x2-x1)x + b
y2 = (y2-y1/x2-x1)x2 + b
b = y2 - (y2-y1/x2-x1)x2
y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]
Choose any points and just
Plug the values and you have a linear function.
NOT SURE IF THAT'S WHAT THE QUESTION WANTS.
20, 180 - 20, 180 + 20 and 360 - 20
i.e. 20°, 160°, 200° and 340°
Step-by-step explanation:
We have,
First terms of geometric sequence, a = 0.3
Common ratio, r = 3
It is required to find the 12th term of a GP. The formula of the nth term is given by :
Here, n =12
So,
or
So, the 12th term of the GP is 53144.
Answer:
Hello, i think that your answer would be c
Step-by-step explanation:
