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EleoNora [17]
3 years ago
9

How do u do this? please help

Mathematics
1 answer:
OLga [1]3 years ago
3 0

Answer:

21

Step-by-step explanation:

Given that 2 parts of the ratio equals 14 green marbles, then divide to find the value of one part of the ratio.

14 ÷ 2 = 7 ← value of 1 part of the ratio, thus there are 7 blue marbles

Total marbles = 14 + 7 = 21

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30 POINT REWARD!!! (haha I need to write 20 characters so that why this is here ps. please help)
aksik [14]

Answer

Sorry, I need points to ask more question.

3 0
2 years ago
Use =, <, or > signs (ratios)
oksano4ka [1.4K]

Answer:

< > > I am pretty sure that is it

5 0
3 years ago
The average of the first five multiple of 7 is
Black_prince [1.1K]

Answer:

b. 21

Step-by-step explanation:

The first five mutiples of 7 are:<em> 7, 14, 21, 28, 35. </em>You can get these by multiplying 7 to any integer.

  • 7x1 = 7
  • 7x2 = 14
  • 7x3 = 21
  • 7x4 = 28
  • 7x5 = 35

In order to get the average of these numbers, you have to add them and divide the sum to the total number of multiples.

Let's add first.

7+14+21+28+35 = 105

Let's divided 105 by 5, which is the number of the multiples of 7.

105÷5 = 21

<em>The answer is 21.</em>

7 0
3 years ago
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
F(-1)=4-3x<br> F(2)=4-3x
konstantin123 [22]
4-3(-1) = 7
4-3(2) = -2
6 0
2 years ago
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