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Svetlanka [38]
3 years ago
6

Carly's family traveled 3/10 of the distance to her grandmother's house on Saturday. They traveled 3/7 of the remaining distance

on Sunday. What fraction of the total distance to her grandmother's house was traveled on Sunday?
Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

3/10 of the total distance to her grandmother's house was traveled on Sunday

Step-by-step explanation:

Carly's family traveled distance of Saturday = \frac{3}{10}

Remaining distance =1-\frac{3}{10}=\frac{7}{10}

They traveled 3/7 of the remaining distance on Sunday.

So, Distance traveled on Sunday =\frac{3}{7}(\frac{7}{10})

Distance traveled on Sunday =\frac{3}{10}

Fraction of the total distance to her grandmother's house was traveled on Sunday =\frac{3}{10}

Hence 3/10 of the total distance to her grandmother's house was traveled on Sunday

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If an angle measuring 20 is bisected to form two new angles, what is the measure of each new angle
alexgriva [62]

Answer:

10 degrees

Step-by-step explanation:

Bisection means dividing into two equal parts

So, if we bisect an angle measuring 20 degrees

It will divide into 2 equal parts and:

=> 20/2 = 10 degrees

Two angles of 10 degrees will be formed.

4 0
3 years ago
Will rate7 you brainliest
Vilka [71]

Answer:

\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)

\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)

\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)

\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)

Now, let's compute the product.

\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}

So the correct answer is the first one.

Thank you.

7 0
3 years ago
What is the value of 6 1/3 - 4 6/7 =
beks73 [17]

Answer:

2 -11/21

Step-by-step explanation

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What is the value of x in the equation -3/4=x/24
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