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liberstina [14]
3 years ago
11

Describe the location of point (−5, −5, 5) in three-dimensional coordinate space.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0
Here's a really cool website that let's you input 3D points!
http://technology.cpm.org/general/3dgraph/

From the attached picture you can see that the point has moved back 5 units, to the left 5 units, and up 5 units.


Mama L [17]3 years ago
4 0

Answer:

Option B is right

Step-by-step explanation:

In 3 dimension we have 8 octants, with x,y, z axes mutually perpendicular.

Given coordinate is (-5,-5,5)

Since x is negative we find move 5 units back first,

y is also negative hence move 5 units left

Z is positive this implies 5 units up

In two dimension we do as follows:

Locate x on the x-axis.

From that point, moving parallel to the y-axis, move y units. This is your point.

IN three dimension we extend as follows:

Locate x on the x-axis.

From that point, moving parallel to the y-axis, move y units.

From that point, moving parallel to the z-axis, move z units. This is your point

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We can set it up like this:
\frac{2}{9}\cdot \frac{9}{5}
Multiply straight...
=\frac{2\cdot \:9}{9\cdot \:5}
Simplify...
=\frac{2}{5}
That's our answer, we can also convert it to decimal.

Answer in fraction form: =\frac{2}{5}
Answer in decimal form: 0.4

Let me know if you have any questions regarding this problem!
Thanks!
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Please give a step by step solution on how to solve #5. Thanks!
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The scented candle burns more in one hour.

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2(5x-7)=2x+10 what Is the distributive property
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4 0
3 years ago
Could someone do all the problems and/or check my work?
MArishka [77]
11. You’ve done it correctly

12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2

13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution

14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath

15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4

Hope this helped :)
8 0
3 years ago
Read 2 more answers
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