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liberstina [14]
3 years ago
11

Describe the location of point (−5, −5, 5) in three-dimensional coordinate space.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0
Here's a really cool website that let's you input 3D points!
http://technology.cpm.org/general/3dgraph/

From the attached picture you can see that the point has moved back 5 units, to the left 5 units, and up 5 units.


Mama L [17]3 years ago
4 0

Answer:

Option B is right

Step-by-step explanation:

In 3 dimension we have 8 octants, with x,y, z axes mutually perpendicular.

Given coordinate is (-5,-5,5)

Since x is negative we find move 5 units back first,

y is also negative hence move 5 units left

Z is positive this implies 5 units up

In two dimension we do as follows:

Locate x on the x-axis.

From that point, moving parallel to the y-axis, move y units. This is your point.

IN three dimension we extend as follows:

Locate x on the x-axis.

From that point, moving parallel to the y-axis, move y units.

From that point, moving parallel to the z-axis, move z units. This is your point

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The probability, P, that a person responds to an advertisement can be modeled by the exponential function P = 1 – e^-0.047t. In
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The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3

<h3>How to create the sine function?</h3>

A sine function is represented as:

f(x) = A sin(B(x + C)) + D

Where

A = Amplitude

Period = 2π/B

C = Phase shift

D = Vertical shift

The requirements in the question are:

  • Amplitude not equal to 1
  • Period not equal to 2π
  • Non-zero phase and vertical shifts

So, we can use the following assumptions

A = 2

Period = 4

C = 6

D = -3

So, we have:

f(x) = 2 sin(B(x + 6)) - 3

The value of B is

4 = 2π/B

This gives

B = π/2

So, we have:

f(x) = 2 sin(π/2(x + 6)) - 3

<h3>The amplitude, vertical shift, period of f(x)and the phase shift</h3>

Using the representations in (a), we have:

  • Amplitude = 2
  • Vertical shift = -3
  • Period = 4
  • Phase shift = 6

<h3>The graph of the function</h3>

See attachment for the graph of f(x)

<h3>The value of cos θ </h3>

Let θ = 3π

So, we have:

cos(3π)

This is calculated as:

cos(3π) = cos(2π + π)

Expand

cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)

Evaluate

cos(3π) = -1

<h3>The value of sin θ </h3>

Let θ = 3π

So, we have:

sin(3π)

This is calculated as:

sin(3π) = sin(2π + π)

Expand

sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)

Evaluate

sin(3π) = 0

<h3>The value of tan 2θ </h3>

Let θ = 3π

So, we have:

tan(2 * 3π)

tan(6π)

This is calculated as:

tan(6π) = tan(3π + 3π)

Evaluate

tan(3π) = 0

Read more about sinusoidal functions at:

brainly.com/question/10700288

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