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2 years ago

What is 57/100- 3/10

Mathematics

2 answers:

Lena [83]2 years ago

5 0

Answer:

27/100

Step-by-step explanation:

make 3/10 into an equivalent fraction with a denominator of 100

therefore, multiply both 3 and 10 by 10 to get: 30/100

57/100 - 30/100 = 27/100

blagie [28]2 years ago

4 0

<h3><u>Answer:</u></h3>

27/100

<h3><u>Step-by-step explanation:</u></h3>

57/100 - 3/10
=> 57/100 - 30/100
=> 27/100
Therefore, 27/100 is your answer.

<h3><u>Conclusion:</u></h3>

Hoped this helped

$BrainiacUser1357$

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Kim purchased a dress that was originally $35. It was on sale for 30% off. She also bought a pair of shoes for 1/2 off the origi

LUCKY_DIMON [66]

Answer: $34.32

Step-by-step explanation: We first calculate the price of the dress that was on sale. 30% of 35 is 35/10 x3. This is equal to 3.5x3 which is 7+3.5 = 10.5 We subtract this from 35 to get $24.5. So, the dress cost $24.5. Next 1/2 of 17 is 8.5. In total, the items cost $24.5+$8.5 = $33. Then, there is a 4% sales tax we have to add on to 33. 1% of 33 is 33/100 which is 0.33. This time 4 is 1.32. 33+1.32 is 34.32.

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1 year ago

9. An article was sold at a profit of 12%. Had it been sold for Nu 80 more, there would be a profit of

Kamila [148]

Answer:

<em>The cost price of the article was Nu 1,000</em>

<em>The original selling price was Nu 1,120</em>

<em>The second selling price was Nu 1,200</em>

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

x = Original selling price of the article

y = Cost of the article

The first condition implies that the difference between the selling price and the cost price (the profit) is 12%. Recall the profit % is always calculated with respect to the cost, that is, the profit at the first condition is:

0.12y = Original profit

Setting up the equation, we have:

$x-y=0.12y$

The second condition states the selling price is 80 Nu more than before, that is:

x+80= Second selling price of the article

y = Cost of the article (it doesn't change)

The profit of this condition is 20%, thus:

0.2y = Second profit

This produces a second equation:

$x+80-y=0.2y$

Let's put both equations together to form a system of equations:

$x-y=0.12y$

$x+80-y=0.2y$

Operating on both equations:

$x=1.12y$

$x=1.2y-80$

Equating both equations, we have an equation with only y's:

$1.12y=1.2y-80$

Subtracting 1.2y on each side:

$1.12y-1.2y=-80$

Operating:

$-0.08y=-80$

Solving:

$\displaystyle y=\frac{-80}{-0.08}=1,000$

The cost price of the article was Nu 1,000

b) The selling price of the article will be calculated in both cases:

Original selling price: x=1.12y= 1.12*1000=1,120

The original selling price was Nu 1,120

The second selling price was x+80=1,200

The second selling price was Nu 1,200

8 0

3 years ago

Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t

frozen [14]

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

$c^{2} =a^{2}+b^{2}+2abcos\alpha$ ---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and $\alpha$ is the angle between a and b .

In equation 1 , the maximum and minimum values of $cos\alpha$ are 1 and -1.

so the value of c lies in between

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Given a=13.2 and b=6.7 so the the side lies in between |13.2-6.7| and |13.2+6.7|

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3 0

3 years ago

Help me with this one plz

Zina [86]

C is your answer! If you take away the 25.5 from 60 and divide that my 2 your answer is 17.25!

7 0

3 years ago

Y-x=15 y-x=5 using elimination

Galina-37 [17]

Answer:

No solution

Step-by-step explanation:

To eliminate is to get rid of one of the variables.

You can choose to either add each term in the equations or subtract each term in the equation.

For a variable to be eliminated, there must one pair that have the same constant with it. Each equation already has the same constant with a variable.

Try adding them.

. y - x = 15

2y - 2x = 20 No variables were eliminated.

Try subtracting.

. y - x = 15

0y - 0x = 10 All variables were eliminated.

. 0 = 10 This is false.

This system of equations cannot be solved.

Graphically, these two lines would have the same slope and are parallel. The solution to a system is same as the point of intersection. Parallel lines never meet, never intersect, therefore there is no solution.

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3 years ago