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bekas [8.4K]
3 years ago
8

Sofia takes 10mg of a medicine whose concentration in blood decreases by a factor of one half every day. Let t be the number of

days since Sofia took the medication. The amount of medication in her system after t days is S = 10(½)t.
Four days later, Lexi takes 10mg of the same medicine. How much medication, L, is in Lexi’s system on day t?

L = 10(1/2)t

L = 10(1/2)t + 4

L = 10(1/2)t – 4

L = 10(1/2)4t
Mathematics
2 answers:
Agata [3.3K]3 years ago
6 0

Answer:

C.  L=10(1/2)^t-4

Second Part A. L=16xS

Step-by-step explanation:

Edge 2020

adelina 88 [10]3 years ago
3 0

Answer:

L = 10(\frac{1}{2} )^{t-4}

Step-by-step explanation:

If t is the number of days since Sofia took the medication of 10 mg, then the amount of medication in her system after t days will be S = 10(\frac{1}{2} )^{t}.

So, the concentration of medicine in blood decreases by a factor of one half every day.

If we count the number of days from today and Lexi takes 10 mg of the same medicine four days later then the amount of medicine left on her body after t days will be L = 10(\frac{1}{2} )^{t-4}. (Answer)

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Your question has been heard loud and clear.

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Hello from MrBillDoesMath!

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