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2 years ago

17х+3 – 5у + 19 + 10z

Mathematics

1 answer:

Verizon [17]2 years ago

7 0

Answer:

If your looking for the Coefficient it is 17

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0.3(4-x)=x-1.4 how do you solve this problem?

tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer: x = 2.

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2 years ago

Hello<br> I have to write at least 20 words to say hi.

maksim [4K]

Hi

I have to write at least 20 words to say hello.

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2 years ago

Hi can someone help please

ankoles [38]

Answer:

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5 0

3 years ago

Read 2 more answers

Solve for p: p + 2x = 4

lyudmila [28]

Answer:

p=4-2x

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The height of a triangle is 4 sqrt 3 . What is the perimeter of the equatorial triangle?

Karo-lina-s [1.5K]

The perimeter of the equatorial triangle is 24 units

<h3><u>Solution:</u></h3>

Given that,

An equilateral triangle has an height equal to $4 \sqrt{3}$

The triangle is shown below

From Triangle ABC in the shown figure AD $=4 \sqrt{3}$

Let the sides of the equilateral triangle be ‘a’

AB = BC = a

Since, it is an equilateral triangle we get,

BD = DC = a ÷ 2

Now, using Pythagoras Theorem in Triangle ABD,

The Pythagorean theorem is this: In a right triangle, the sum of the squares of the lengths of the two legs is equal to the square of the length of the hypotenuse.

$\mathrm{AB}^{2}=\mathrm{BD}^{2}+\mathrm{AD}^{2}$

$\begin{array}{l}{a^{2}=\left(\frac{a}{2}\right)^{2}+(4 \sqrt{3})^{2}} \\\\ {a^{2}-\left(\frac{a}{2}\right)^{2}=(4 \sqrt{3})^{2}}\end{array}$

$\frac{4 a^{2}-a^{2}}{4}=16 \times 3$

$\begin{array}{l}{\frac{3 a^{2}}{4}=16 \times 3} \\\\ {3 a^{2}=192} \\\\ {a^{2}=192 \div 3=64}\end{array}$

a = 8

Hence, the three sides of the triangle are 8 units each

In equilateral traingle, length of all three sides of triangle are equal

So, Perimeter = 3 $\times$ (Length of each side of triangle)

Perimeter = 3 $\times$ 8 = 24

Thus the perimeter of the equatorial triangle is 24 units

7 0

3 years ago