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Arisa [49]
3 years ago
15

-4 1/5 - { -13 1/10}

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0

Answer:

Mixed number: 4 9/10

Decimal: 4.9

Exact Form: 49/10

Step-by-step explanation:

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What is the geometrick mean of 27 and 8 with the pothagereom theorem
enyata [817]

Answer:

x = 6√6

Step-by-step explanation:

27/x = x/8

x² = 27 × 8

x = √(27 × 8)

x = √(9 × 4 × 6)

x = 3 × 2 × √6

x = 6√6

5 0
2 years ago
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SOLVE: 6^3x+2 = 4^x-5
Lilit [14]
There's an app called photomath that would be useful for these kinds of problems!
6 0
3 years ago
Find the equation of the exponential function represented by the table below:​
aivan3 [116]

Answer:

I believe its y=5(4)^x

Step-by-step explanation:

The equation is supposed to look like y=ab^x

a is basically where it all starts, so where the y meets the 0

- so the 5 in the y's place meets the 0

b is what you're multiplying by on the y's side, which is by 4 every time

and the x is the exponent and since there is no exponent you leave it as x

4 0
3 years ago
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?
VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is r_{(90^\circ, O)}(WXYZ).

To find:

The vertices after rotation.

Solution:

We know that, r_{(90^\circ, O)}(WXYZ) means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

(x,y)\to (-y,x)

Using this rule, we get

W(3,-5)\to W'(5,3)

X(1,-3)\to X'(3,1)

Y(-1,-5)\to Y'(5,-1)

Z(1,-7)\to Z'(7,1)

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0
3 years ago
Can someone help me understand this.​
3241004551 [841]

Answer:

easy-peasy

Step-by-step explanation:

Perimeter:

P=2(a+b)

P=2(50+70)

P=2(120

P=240

Area:

A=50*70

A=3,500

I really hope it helped:)

8 0
3 years ago
Read 2 more answers
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