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3 years ago

6

Select all the correct systems of equations. Which systems of equations have infinite solutions?

1 answer:

nikklg [1K]3 years ago

6 0

Answer: Comment: From the explanations below,

2x + y = 10

-6x = 3y + 7 had an infinite solution, while y = 14 -2x

6x + 3y = 42 has a fictitious solution, so also equation

2x + y = 17

-6x = 3y - 51.

Step-by-step explanation:

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iDentify the equation of the circle that has its center at (-27, 120) and passes through the origin A. (x−27)2+(y+120)2=123 B. (

melomori [17]

The equation of a circle is given in the form $(x-a)^2+(y-b)^2=r^2$ , where

(a, b) is the centre of the circle
r = radius

We have the centre of the circle (-27, 120)
We can work out the radius by modelling the radius as the hypotenuse of a triangle as shown in the diagram below

$r^2=27^2+120^2$
$r^2 = 15129$

The equation of the circle is

$[x-(-27)]^2+[y-120]^2=15129$
$[x+27]^2+[y-120]^2=15129$

Correct answer: option number 4

7 0

3 years ago

Please answer below :-)

katrin2010 [14]

Step-by-step explanation:

$\frac{2x - 1}{4} + \frac{x}{3} = 2$

find a common denominator of 12 for each fraction

$\frac{3}{3} \times \frac{(2x - 1)}{4} + \frac{4}{4} \times \frac{x}{3} = \frac{12}{12} \times \frac{2}{1}$

$\frac{6x - 3}{12} + \frac{4x}{12} = \frac{24}{12}$

$\frac{6x - 3 + 4x}{12} = \frac{24}{12}$

$\frac{10x - 3}{12} = \frac{24}{12}$

multiply both sides by 12

$12 \times \frac{10x - 3}{12} = \frac{24}{12} \times 12$

12s cancel out

$10x - 3 = 24$

add three to both sides

$10x - 3 + 3 = 24 + 3$

$10x = 27$

divide both sides by 10

$\frac{10x}{10} = \frac{27}{10}$

The tens on the left side cancel

$x = \frac{27}{10} = 2.7$

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Aleksandr-060686 [28]

NO is 2 times LM

2(x+1) = 4x

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