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Nadusha1986 [10]
2 years ago
15

How many sides does a square pyramid have

Mathematics
1 answer:
slamgirl [31]2 years ago
3 0
A square pyramid has 5 sides.

hope this helps!
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Theater m has 25 rows with 27 seats in each row. how many of the seats were occupiedduring a certain show?(1) during the show, t
Elis [28]
1) 475
2)375
You need to multiply 25 by 27 and you get 675 then to get answer one you need to multiply 10 by 20 to get 200 the take 200 away from 675 to get 475 then do the same thing with the second problem 20x15 which is 300 the take 300 away from 675.
5 0
3 years ago
Using quadratic form 6x^2-8x+3=0
LenaWriter [7]

x=8+sqrt-8/12, x=8-sqrt-8/12

I think...

5 0
2 years ago
What is the mathematical sentence of "A number increasd by 7 is 15?
svet-max [94.6K]

Answer:

B

Step-by-step explanation:

A number increased by 7 means, 7 was added to the number and the result is 15

6 0
2 years ago
Please help with this question, I need the help urgently
grin007 [14]

Answer:

P in terms of V is:

P = 432/V

Step-by-step explanation:

We know that y varies inversely as x, we get the equation

y ∝ 1/x

y = k/x

k = yx

where k is called the constant of proportionality.

In our case,

P is inversely proportional to V

Given

P = 18

V = 24

so

P = k/V

k = PV

substituting P = 18 and V = 24 to determine k

k = 18 × 24

k = 432

now substituting k = 432 in P = k/V

P =  432/V

Therefore, P in terms of V is:

P = 432/V

5 0
3 years ago
Which of the following is the complete list of roots for the polynomial function f (x) = (x squared 6 x 8) (x squared 6 x 13)? –
Sunny_sXe [5.5K]

The roots of the given polynomial function is {-4, -2, -3 + 2i, -3 - 2i}.

<h3>How to get the roots of the polynomial?</h3>

Here we have the polynomial function:

f(x) = (x^2 + 6x + 8)*(x^2 + 6x + 13)

So we just need to find the roots of the two quadratic functions, to do that, we use Bhaskara's formula.

For the first one, we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*8} }{2} \\\\x = \frac{-6 \pm 2}{2}

So the two solutions are:

x = (-6 - 2)/2 = -4

x = (-6 + 2)/2 = -2

For the second quadratic we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*13} }{2} \\\\x = \frac{-6 \pm 4i}{2}

So the two solutions are:

x = -3 + 2i

x = -3 - 2i

Finally, the list is:

{-4, -2, -3 + 2i, -3 - 2i}

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ4

8 0
2 years ago
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