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elena55 [62]
3 years ago
8

Tyreese is using algebra tiles to solve the equation below.

Mathematics
2 answers:
shtirl [24]3 years ago
6 0

Answer: step 3 is the correct first step

Step-by-step explanation:

Let us number the steps

1) Tyreese’s first step is to

remove one x-tile from both sides.

2) remove two x-tiles from the left side.

3) add one positive x-tile to both sides.

4) add two positive x-tiles to both sides.

The equation which Tyreese wants to solve is

2x + 5 = - x + ( -1 ). The aim is to make x to be on only one side

1) If she applies step 1, it becomes

2x - x + 5 = - x - x + ( -1 )

x + 5 = -2x - 1

x is still on both sides, so step 1 is wrong.

2) If she applies step 2, it becomes

2x - 2x + 5 = - x + ( -1 )

5 = -x - 1

step 2 is wrong because whatever you do to the left hand side must also be done to the right hand side. So 2x must be removed from both sides.

3) If she applies step 3, it becomes

2x +x + 5 = - x + x + ( -1 )

3x + 5 = - 1

x is on only the left hand side of the equation, so step 3 is right.

4) If she applies step 4, it becomes

2x + 2x + 5 = - x + 2x + ( -1 )

4x + 5 = x - 1

x is still on both sides, so step 4 is wrong.

Alex787 [66]3 years ago
4 0

Answer:

add one positive x-tile to both sides.

Step-by-step explanation:

3) If she applies to step 3, it becomes

2x +x + 5 = - x + x + ( -1 )

3x + 5 = - 1

x is on only the left-hand side of the equation, so step 3 is right.

Consider the provided equation.

2x + 5 = -x + 1

Now to solve the above equation first isolate the variables.

To isolate the variables add x to both the side of the equation.

2x + 5 + x = -x + 1 + x

Now add the like terms.

3x + 5 =  1

Here we add the x tiles to both the side of the equation.

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Solution:

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Step-by-step explanation:

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3 years ago
Robert believes that the lengths 8 in, 13 in, and 20 in will form a triangle. Is he correct?
adell [148]

Answer: I think it’s D

Step-by-step explanation:

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7 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

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3.1.3 Quiz: Two-Variable Systems: Graphing
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Answer:

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Step-by-step explanation:

imagine cheating

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